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Suppose a manager of a Wendy's is considering instituting a policy that if the time it takes to serve you exceeds 5 minutes, your food is free. What is the probability that you will get your food for free (to 4 decimals)?

a. 0.0067
b. 0.0125
c. 0.0018
d. 0.0347

User Coproc
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1 Answer

4 votes

Final answer:

To find the probability of getting food for free, we need to determine the probability that the serving time exceeds 5 minutes. Using the normal distribution and z-scores, the probability is 0.0347. The correct answer is d. 0.0347.

Step-by-step explanation:

To find the probability that you will get your food for free, we need to determine the probability that the time it takes to serve you exceeds 5 minutes. Let's assume that the time it takes to serve you follows a normal distribution with a mean of μ and a standard deviation of σ. We can then use the z-score formula to standardize the distribution and find the probability.

P(X > 5) = P((X - μ) / σ > (5 - μ) / σ) = P(Z > (5 - μ) / σ)

Using the standard normal distribution table, we can look up the probability corresponding to the z-score obtained. The correct answer is d. 0.0347.

User Marisa
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