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Using division, what is the quotient (2x^3 −2x−12)÷(x−2)?

a. 2x^2 −4x+6
b. 2x^2 −4x
c. 2x^2 +4x−6
d. 2x^2 +4x+6

1 Answer

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Final answer:

To find the quotient (2x^3 - 2x - 12) ÷ (x - 2) using division, use long division and follow the steps carefully. The final quotient is 2x^2 - 4x + 6.

Step-by-step explanation:

To find the quotient (2x^3 - 2x - 12) ÷ (x - 2) using division, you can use long division.

Step 1: Divide the first term of the dividend (2x^3) by the divisor (x - 2). The result is 2x^2.

Step 2: Multiply the divisor (x - 2) by the result from step 1, which is 2x^2. The result is 2x^3 - 4x^2.

Step 3: Subtract the product from step 2 from the dividend. The result is -4x^2 - 2x - 12.

Step 4: Repeat steps 1-3 with the new dividend (-4x^2 - 2x - 12) until you have no more terms to divide.

The final quotient is 2x^2 - 4x + 6.

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