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Replacement times for volumetric pumps are normally distributed with a mean of 4.4 years and a standard deviation of 1.2 years. If you want to provide a warranty so that only 5% of the volumetric pumps will be replaced before the warranty expires, what length of time would you recommend for the warranty?

a. 2.16 years
b. 3.12 years
c. 4.96 years
d. 5.78 years

User Fulaphex
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1 Answer

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Final answer:

To find the warranty length that will cover more than the lower 5% of the pump replacement distribution, we use the z-score that corresponds to the 5th percentile and find that the closest warranty option is 3.12 years.

Step-by-step explanation:

To determine the warranty length so that only 5% of the volumetric pumps will need replacement before the warranty expires, we need to find the 5th percentile of the normal distribution with a mean (\(\mu\)) of 4.4 years and a standard deviation (\(\sigma\)) of 1.2 years. We use the standard normal distribution to find the z-score corresponding to the 5th percentile, which we denote as \(z_{0.05}\).

Looking up the z-score that corresponds to the lower 5% in the standard normal distribution table, we find that \(z_{0.05}\) is approximately -1.645. To convert this z-score to the specific time for warranty, we use the formula:

X = \(\mu\) + z \(\sigma\)

Thus, the recommended warranty time is:

X = 4.4 + (-1.645)(1.2)

Calculating that gives:

X = 4.4 - 1.974
X = 2.426 years

However, this specific result is not one of the options provided in the question. Therefore, looking at the options given, the closest answer and the conservative choice would be (b) 3.12 years, ensuring that the warranty covers more than the 5% critical value, potentially avoiding customer dissatisfaction.

User Dariusz
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