Question

State the steps involved in preparing a 0.530 M Cu(CH₃CO₂)₂ (copper(II) acetate) solution.

a) Dissolve 0.530 moles of Cu(CH3CO2)2 in 1 liter of solvent
b) Dissolve 0.530 grams of Cu(CH3CO2)2 in 1 liter of solvent
c) Dissolve 0.530 grams of Cu(CH3CO2)2 in 500 mL of solvent
d) Dissolve 0.530 moles of Cu(CH3CO2)2 in 500 mL of solvent

Answer 1

To prepare a 0.530 M Cu(CH₃CO₂)₂ (copper(II) acetate) solution, you would determine the molar mass of Cu(CH₃CO₂)₂ and calculate the amount needed based on the desired molarity and volume. Then, you would weigh out the calculated amount and dissolve it in the desired solvent.

Step-by-step explanation:

To prepare a 0.530 M Cu(CH₃CO₂)₂ (copper(II) acetate) solution, you would follow these steps:

1. Determine the molar mass of Cu(CH₃CO₂)₂ (molar mass = 181.63 g/mol)
2. Calculate the amount of Cu(CH₃CO₂)₂ needed by multiplying its molar mass by the desired molarity (0.530 M) and the volume of the solution (in liters)
3. Weigh out the calculated amount of Cu(CH₃CO₂)₂
4. Dissolve the weighed Cu(CH₃CO₂)₂ in the desired amount of solvent (e.g., 1 liter or 500 mL) and mix well to ensure complete dissolution