Question

Solve the simultaneous equations 2x 3y=2/3 3x-4y=18

a. x=5,y=−2
b. x=−2,y=5
c. x=3,y=−3
d. x=−3,y=3

Answer 1

To solve this system of equations, we can use the method of substitution. By solving for one variable in terms of the other, we can substitute this expression into the other equation. Solving for both x and y, we find that the solution is x = 5 and y = -2.

Step-by-step explanation:

To solve the system of equations, we can use the method of substitution. We have the following two equations:

2x - 3y = 2/3

3x - 4y = 18

From the first equation, we can solve for x in terms of y: x = (2/3 + 3y)/2

Substituting this value of x into the second equation, we have: 3((2/3 + 3y)/2) - 4y = 18

Simplifying and solving for y, we get y = -2.

Substituting y = -2 back into the first equation, we can solve for x: 2x - 3(-2) = 2/3

Simplifying this equation, we get x = 5.

Therefore, the solution to the simultaneous equations is x = 5 and y = -2. This matches option a. x=5, y=−2.