Question

There are 9 balls numbered 1 through 9 placed in a bucket. What is the probability of reaching into the bucket and randomly drawing two balls numbered 6 and 2 without replacement, in that order? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Answer 1

The probability of drawing a ball numbered 6 and then a ball numbered 2 from a bucket of 9 numbered balls without replacement is 1/72.

Step-by-step explanation:

The total number of balls in the bucket is 9. Since we are drawing two balls without replacement, the total number of possible outcomes is 9 * 8 = 72 (9 choices for the first ball and 8 choices for the second ball).

The probability of drawing the ball numbered 6 first is 1/9, as there is only one ball numbered 6 out of 9 balls in the bucket.

After drawing the ball numbered 6 from the bucket, there are 8 balls left, with only one ball numbered 2. Therefore, the probability of drawing the ball numbered 2 second is 1/8.

To find the probability of both events happening in sequence, we multiply the individual probabilities together: (1/9) * (1/8) = 1/72.