Final answer:
The train will travel 210 meters in 6.0 seconds due to deceleration with an average acceleration of -5.0 m/s² starting from an initial velocity of 50 m/s.
Step-by-step explanation:
In this case, the train is decelerating with an average acceleration of -5.0 m/s² (negative sign shows deceleration). To find how far it travels in 6.0 seconds, we can use the equation:
d = v0t + (1/2)at2
Where d represents the distance, v0 is the initial velocity, t is the time, and a is the acceleration.
Plugging in the values:
d = (50 m/s)(6.0 s) + (1/2)(-5.0 m/s²)(6.0 s)2
d = 300 m - 90 m = 210 m
Therefore, the train travels 210 meters in 6.0 seconds.