Question

Remember to identify all your data, write the equation, and show your work. A train is slowing down with an average acceleration of −5.0 m/s² (negative sign shows deceleration). If its initial velocity is 50. m/s, how far does it travel in 6.0 seconds?

a. 125 meters
b. 150 meters
c. 175 meters
d. 200 meters

Answer 1

The train will travel 210 meters in 6.0 seconds due to deceleration with an average acceleration of -5.0 m/s² starting from an initial velocity of 50 m/s.

Step-by-step explanation:

In this case, the train is decelerating with an average acceleration of -5.0 m/s² (negative sign shows deceleration). To find how far it travels in 6.0 seconds, we can use the equation:

d = v0t + (1/2)at2

Where d represents the distance, v0 is the initial velocity, t is the time, and a is the acceleration.

Plugging in the values:

d = (50 m/s)(6.0 s) + (1/2)(-5.0 m/s²)(6.0 s)2

d = 300 m - 90 m = 210 m

Therefore, the train travels 210 meters in 6.0 seconds.