Question

There are 135 L of gas in a container at a temperature of 260 degrees Celsius. If the gas was cooled until the volume decreased to 75 L, what would the temperature of the gas be?

Answer 1

When a gas in a container at 260 °C and 135 L is cooled until its volume decreases to 75 L, the new temperature of the gas would be approximately 23.43 °C.

Step-by-step explanation:

To determine the new temperature of the gas when it's cooled until its volume decreases to 75 L, we can use Charles's Law. Charles's Law states that for a given amount of gas at constant pressure, the volume of the gas is directly proportional to its temperature in kelvins (V/T = k). Hence, if the initial volume (V1) and temperature (T1) are known, and the final volume (V2) is known, we can solve for the final temperature (T2).

First, we convert the initial temperature from degrees Celsius to kelvins:

T1 = 260 °C + 273.15 = 533.15 K

Using Charles's Law (V1/T1 = V2/T2), we can solve for T2:

(135 L / 533.15 K) = (75 L / T2)

T2 = (75 L * 533.15 K) / 135 L

T2 is approximately 296.58 K, which is about 23.43 °C.