Question

Molarity of 25 ml of 3.8 M NaCl reacting with 198 ml (molar mass =58.5)?

a) 0.48 M
b) 3.64 M
c) 4.26 M
d) 6.12 M

Answer 1

The molarity of the solution is 0.48 M.

Step-by-step explanation:

To find the molarity of a solution, we need to use the equation:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

In this case, we have:

M1 = 3.8 M, V1 = 25 ml, M2 = ?, V2 = 198 ml

Substituting these values into the equation:

(3.8 M)(25 ml) = M2(198 ml)

Solving for M2:

M2 = (3.8 M)(25 ml) / (198 ml) = 0.48 M

Therefore, the molarity of the solution is 0.48 M, which corresponds to option A.