Answer:
The width of a rectangle measures left bracket, 8, c, minus, 5, right bracket(8c−5) centimeters, and its length measures left bracket, 2, c, plus, 10, right bracket(2c+10) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?
The perimeter of a rectangle is the sum of all of its sides:
The perimeter of a rectangle is the sum of all of its sides:
8, c, minus, 5, start subscript, width, end subscript, plus , 8, c, minus, 5, start subscript, width, end subscript, plus , 2, c, plus, 10, start subscript, length, end subscript, plus , 2, c, plus, 10, start subscript, length, end subscript
width
8c−5
+
width
8c−5
+
length
2c+10
+
length
2c+10
8, c, minus, 5, plus, 8, c, minus, 5, plus, 2, c, plus, 10, plus, 2, c, plus, 10
8c−5+8c−5+2c+10+2c+10
8, c, plus, 8, c, plus, 2, c, plus, 2, c, minus, 5, minus, 5, plus, 10, plus, 10
8c+8c+2c+2c−5−5+10+10
start underbrace, 8, c, plus, 8, c, plus, 2, c, plus, 2, c, end underbrace, start subscript, 20, c, end subscript, , start underbrace, minus, 5, minus, 5, plus, 10, plus, 10, end underbrace, start subscript, plus, 10, end subscript
20c
8c+8c+2c+2c
+10
−5−5+10+10
20, c, plus, 10
20c+10
10, plus, 20, c
10+20c
Step-by-step explanation:
The width of a rectangle measures left bracket, 8, c, minus, 5, right bracket(8c−5) centimeters, and its length measures left bracket, 2, c, plus, 10, right bracket(2c+10) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?
The perimeter of a rectangle is the sum of all of its sides:
The perimeter of a rectangle is the sum of all of its sides:
8, c, minus, 5, start subscript, width, end subscript, plus , 8, c, minus, 5, start subscript, width, end subscript, plus , 2, c, plus, 10, start subscript, length, end subscript, plus , 2, c, plus, 10, start subscript, length, end subscript
width
8c−5
+
width
8c−5
+
length
2c+10
+
length
2c+10
8, c, minus, 5, plus, 8, c, minus, 5, plus, 2, c, plus, 10, plus, 2, c, plus, 10
8c−5+8c−5+2c+10+2c+10
8, c, plus, 8, c, plus, 2, c, plus, 2, c, minus, 5, minus, 5, plus, 10, plus, 10
8c+8c+2c+2c−5−5+10+10
start underbrace, 8, c, plus, 8, c, plus, 2, c, plus, 2, c, end underbrace, start subscript, 20, c, end subscript, , start underbrace, minus, 5, minus, 5, plus, 10, plus, 10, end underbrace, start subscript, plus, 10, end subscript
20c
8c+8c+2c+2c
+10
−5−5+10+10
20, c, plus, 10
20c+10
10, plus, 20, c
10+20c