Final answer:
The probability that a randomly selected newborn baby boy will weigh less than 4226 grams is approximately 75.49%, calculated using the z-score and the standard normal distribution.
Step-by-step explanation:
The question involves finding the probability that a newborn baby boy's weight is less than 4226 grams when the weights are normally distributed with a mean of 3988 grams and a variance of 119,716 grams^2. To find this probability, we calculate the z-score and use the standard normal distribution.
First, we find the standard deviation by taking the square root of the variance. The standard deviation (σ) is √119,716 ≈ 346 grams.
Next, we calculate the z-score using the formula:
Z = (X - μ) / σ
Z = (4226 - 3988) / 346
Z ≈ 0.688
Now, we look up this z-score in the standard normal distribution table or use a calculator with a normal distribution function to find the probability, which is the area under the curve to the left of this z-score.
The probability for a z-score of 0.688 is approximately 0.7549, which means there's a 75.49% chance that a randomly selected newborn baby boy will weigh less than 4226 grams.