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The vector is at a 58° angle and has a magnitude of 35. describe this vector using vector notation (use the and symbols.)

User SuperManSL
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Final answer:

To describe a vector with a magnitude of 35 and at a 58° angle using vector notation, we can use the components of the vector. The x-component of V can be calculated using V * cos(θ) and the y-component can be calculated using V * sin(θ). Using these components, we can write the vector V in vector notation as V = 18.14i + 28.68j.

Step-by-step explanation:

To describe a vector with a magnitude of 35 and at a 58° angle using vector notation, we can use the components of the vector. Let's call the vector V. The x-component of V can be calculated as Vx = V * cos(θ), where θ is the angle of the vector. Plugging in the values, Vx = 35 * cos(58°) = 18.14.

The y-component of V can be calculated as Vy = V * sin(θ), where θ is the angle of the vector. Plugging in the values, Vy = 35 * sin(58°) = 28.68.

Using these components, we can write the vector V in vector notation as V = 18.14i + 28.68j, where i and j are the unit vectors along the x and y axes respectively.

User ElBel
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