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The temperature of a sample of water changes from 10.°c to 20.°c when the water absorbs 420 joules of heat. what is the mass of the sample?

a) 42 g
b) 84 g
c) 21 g
d) 10 g

User Akf
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1 Answer

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To find the mass of the sample of water, we can use the equation: Q = mcΔT. Given that ΔT = 20.°C - 10.°C = 10.°C and Q = 420 J, and the specific heat capacity of water is approximately 4.184 J/g°C, we can rearrange the equation to solve for m. Therefore, the mass of the sample of water is 10 g.

To find the mass of the sample of water, we can use the equation:

Q = mcΔT

Where Q is the heat absorbed, m is the mass, c is the specific heat capacity of water, and ΔT is the change in temperature.

Given that ΔT = 20.°C - 10.°C = 10.°C and Q = 420 J, and the specific heat capacity of water is approximately 4.184 J/g°C, we can rearrange the equation to solve for m:

m = Q / (cΔT)

Substituting the given values, we get:

m = 420 J / (4.184 J/g°C * 10.°C) = 10 g

Therefore, the mass of the sample of water is 10 g.

User Mononz
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