Question

The template program for this lab is set to read input: an integer for a year number, and a series of floats in a list variable called sun_hours. these floats in the sun_hours list represent the number of sun hours in highland heights, ky, for every month of the input year. the template program also defines a list variable called moths_of_year that contains strings representing the names of the months of the year. (1) add code to compute and output the average number of sun hours for all months of the input year. (submit for 2 points)

Answer 1

To calculate the average number of sun hours for the year, sum the total sun hours from the sun_hours list and divide by 12. Then, output the average using a print statement.

Step-by-step explanation:

Calculating Average Sun Hours

To compute the average number of sun hours for all months of a given year, one can add the total sun hours for each month and then divide by the number of months, which is 12. Assuming the list sun_hours contains the number of sun hours for each month in the order from January to December, the code to calculate the average would look something like this:

average_sun_hours = sum(sun_hours) / len(sun_hours)

Then, to output the average, you could use a print statement:

print("The average number of sun hours for the year is:", average_sun_hours)

This will give you the average sun exposure for the location specified, Highland Heights, KY, over the course of the input year.

In order to compute and output the average number of sun hours for all months of the input year, you can use the following code:

year = int(input('Enter the year: '))

sun_hours = []

months_of_year = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']

for i in range(12):

sun_hours.append(float(input(f'Enter the number of sun hours for {months_of_year[i]}: ')))

average_sun_hours = sum(sun_hours) / len(sun_hours)

print(f'The average number of sun hours for the year {year} is {average_sun_hours} hours.')