Final answer:
To find the final temperature when 3.50 x 10^4 joules of heat are added to a 454 gram sample of iron at 24.00°C, use the equation Q = mcΔT.
Step-by-step explanation:
To find the final temperature when 3.50 x 104 joules of heat are added to a 454 gram sample of iron at 24.00°C, we can use the equation Q = mcΔT. Q represents the amount of heat added, m is the mass of the iron sample, c is the specific heat of iron, and ΔT is the change in temperature.
Given:
- Q = 3.50 x 104 J
- m = 454 g
- c = 0.448 J/g°C
- Initial temperature (Tinitial) = 24.00°C
- Final temperature (Tfinal) = unknown
Substitute the known values into the equation:
3.50 x 104 J = (454 g)(0.448 J/g°C)(Tfinal - 24.00°C)
Solve the equation for Tfinal:
Tfinal - 24.00°C = (3.50 x 104 J) / (454 g)(0.448 J/g°C)
Tfinal - 24.00°C = 174.56
Tfinal = 198.56°C
Therefore, the final temperature of the iron sample will be 198.56°C.