Question

The slope of a line is 5/8, and the line passes through the point (-8-4). what is the slop intercept form of tje equation for this line?

a. y = (5/8)x + 36
b. y = (5/8)x - 36
c. y = (8/5)x + 36
d. y = (8/5)x - 36

Answer 1

The slope-intercept form of the equation for this line is y = (5/8)x + 1.

Step-by-step explanation:

To find the equation of a line in slope-intercept form (y = mx + b), we need the slope (m) and the y-intercept (b).

In this case, the slope is 5/8 and the line passes through the point (-8, -4).

Using the point-slope form of a line, we can substitute the values into the equation:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line.

So, substituting the values, we have:

y - (-4) = 5/8(x - (-8))

Simplifying the equation gives:

y + 4 = 5/8(x + 8)

Further simplifying, we get:

y + 4 = 5/8x + 5

Subtracting 4 from both sides:

y = 5/8x + 1

Therefore, the slope-intercept form of the equation for this line is y = (5/8)x + 1.