Question

The probability of a team having a sellout crowd is P=0.45. The probability of having a sellout crowd and the team winning is P=0.32. Hence, the probability of a team winning, given that they have a sellout crowd, is:

A) 0.32
B) 0.45
C) 0.71
D) 0.25

Answer 1

The probability of a team winning, given that they have a sellout crowd, is 0.71 (C).

Step-by-step explanation:

The probability of a team winning, given that they have a sellout crowd, can be calculated using the formula for conditional probability:

P(A|B) = P(A AND B) / P(B)

In this case, A represents the event of the team winning and B represents the event of a sellout crowd.

Given that the probability of having a sellout crowd is P(B) = 0.45 and the probability of having a sellout crowd and the team winning is P(A AND B) = 0.32, we can substitute these values into the formula:

P(A|B) = 0.32 / 0.45 = 0.71

Therefore, the probability of a team winning, given that they have a sellout crowd, is 0.71 (C).