Question

Suppose the roller coaster in fig. 6-41 (h1 = 32 m, h2 = 15 m, h3 = 20) passes point 1 with a speed of 1.80 m/s. if the average force of friction is equal to one sixth of its weight, with what speed will it reach point 2? the distance traveled is 60.0 m.

A)2.40 m/s

B)2.00 m/s

C)1.50 m/s

D) 1.20 m/s

Answer 1

The final speed at point 2 of the roller coaster is found by considering the transformation of potential energy into kinetic energy as the coaster moves from h1 to h2, and the work done against friction over the given distance.

Step-by-step explanation:

The student is asking about the final speed of a roller coaster as it reaches point 2 given that it starts with a speed of 1.80 m/s at point 1, the heights of the hills, and the frictional force being a sixth of the coaster's weight over a distance of 60.0 m. To calculate the final speed at point 2, we need to consider the loss of potential energy as the roller coaster descends from height h1 to h2, the initial kinetic energy at point 1, and the work done by friction. By applying the principle of conservation of energy and taking into account the work done against friction, we'll be able to determine the final speed of the roller coaster at point 2.