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Suppose you are given a 105 V motor that draws 9.5 A at its normal (steady-state) speed, but 18.5 A when it first starts. What is the power consumed by the motor during the start-up phase?

A) 105 W

B) 199.25 W

C) 999.75 W

D) 1947.5 W

User Roberth
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1 Answer

3 votes

Final answer:

The power consumed by the motor during start-up is found using the formula P = IV. With a current of 18.5 A and a voltage of 105 V, the power is 1942.5 W, closest to option D).

Step-by-step explanation:

The power consumed by the motor during the start-up phase can be calculated using the formula P = IV, where P is power in watts, I is current in amperes, and V is voltage in volts. Given that the motor draws an initial current of 18.5 A and operates at a voltage of 105 V, the power consumed during start-up can be calculated as follows:

P = IV

P = 105 V × 18.5 A

P = 1942.5 W

Therefore, the power consumed by the motor during the start-up phase is 1942.5 watts, which is closest to option D).

User Darrielle
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