Question

Two substances a and b initially at different temperatures come into contact and reach thermal equilibrium. the mass of substance a is 6.15 g and its inital temperature is 20.5c. the mass of substance b is 25.2g and its inital temperature is 52.7c. the final temperature of both substances at thermal equilibrium is 46.7c. if the specific heat capacity of substances b is 1.17 j/g*c, what is the specific heat capacity of substance a?

Answer 1

To find the specific heat capacity of substance a, use the formula Q = mcΔT and rearrange the equation to solve for c. Substituting the known values, find the specific heat capacity of substance a.

Step-by-step explanation:

To find the specific heat capacity of substance a, we can use the formula:

Q = mcΔT

Where:

• Q is the heat transferred (in joules)
• m is the mass (in grams)
• c is the specific heat capacity (in joules/gram °C)
• ΔT is the change in temperature (in °C)

For substance a:

• m = 6.15 g
• ΔT = (46.7 - 20.5) °C = 26.2 °C

Using the equation, we have:

Q = (6.15 g)(c)(26.2 °C)

Now, to find the specific heat capacity of substance a, we rearrange the equation:

c = Q / (mΔT)

Substituting the known values, we get:

c = Q / (6.15 g)(26.2 °C)

c = Q / 161.43 g °C