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Two golf balls are hit in the air at 66 feet per second (45 mi/hr), making angles of 37 degrees and 53 degrees with the horizontal. If the ground is level, estimate the horizontal distance traveled by each golf ball.

A) Both golf balls will travel the same horizontal distance.
B) The golf ball with a 37-degree angle will travel a greater horizontal distance.
C) The golf ball with a 53-degree angle will travel a greater horizontal distance.
D) The horizontal distances cannot be estimated without additional information.

User Hereiam
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Final answer:

Two golf balls hit at different angles with the same initial speed will travel different horizontal distances due to the varying horizontal components of their initial velocities. The golf ball hit at 37 degrees will travel further than the one hit at 53 degrees, according to projectile motion principles.

Step-by-step explanation:

The question involves calculating the horizontal distance traveled by two golf balls hit with the same initial speed but at different angles. To solve this, we use principles of projectile motion, where the horizontal distance (range) can be found using the formula R = (v^2 ∙ sin(2θ)) / g, where v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.

For the golf balls hit at 37 degrees and 53 degrees, we first convert the speed from feet per second to meters per second for consistency with the gravity constant (g = 9.8 m/s^2). We can ignore air resistance for this estimation. Using trigonometry, we calculate the horizontal components of the initial velocities. The ball hit at a lower angle (37 degrees) will have a larger horizontal component, and therefore, under ideal conditions, it will travel a greater horizontal distance compared to the ball hit at 53 degrees. Hence, the correct answer is B) The golf ball with a 37-degree angle will travel a greater horizontal distance.

User Emmanuel Keller
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