Question

Two kayakers, a and b, live on opposite sides of a 350.0 m wide river that flows west at 0.67 m/s. 'a' lives on the north side and 'b' lives on the south side. they both set out to visit a mutual friend '×' who lives on the north side at a point 150.0 m upstream from a and 150.0 m downstream from b. both kayakers can travel at 2.25 m/s through the water. which kayaker will arrive at x first, and by how much time (in seconds)?

Answer 1

Kayaker A will arrive at the mutual friend first, with a time difference of 22.22 s.

Step-by-step explanation:

To determine which kayaker will arrive at the mutual friend first and by how much time, we need to compare their travel times. Let's calculate the travel times for kayakers A and B:

1. Kayaker A's travel time = distance/speed = 150.0 m/2.25 m/s = 66.67 s
2. Kayaker B's travel time = distance/speed = 200.0 m/2.25 m/s = 88.89 s

Kayaker A will arrive at the mutual friend's location first, with a time difference of 88.89 s - 66.67 s = 22.22 s