Question

Two (2) point charges , each with 0.1c of charge, are 0.1 meter apart. given that k=9.0x109 nm 2 /c 2, show that the force between the charges is 9.0x109 n.

Answer 1

The force between two point charges can be calculated using Coulomb's law. In this case, the force between the charges is 9.0x10^9 N.

Step-by-step explanation:

The force between two point charges can be calculated using Coulomb's law:

F = k * q1 * q2 / r^2

where F is the force, k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between the charges.

In this case, we have q1 = 0.1c, q2 = 0.1c, and r = 0.1 m. Plugging in these values, we get:

F = (9.0x10^9 Nm^2/C^2) * (0.1c) * (0.1c) / (0.1m)^2 = 9.0x10^9 N

Therefore, the force between the charges is 9.0x10^9 N.