Final answer:
The partial pressure of nitrogen in a tank of trimix 10/50 with a total pressure of 2.07×104 kPa is 8.3×103 kPa, calculated by multiplying the total pressure by the fraction of nitrogen in the mixture.
Step-by-step explanation:
The question at hand involves calculating the partial pressure of nitrogen in a tank of trimix 10/50 gas mixture, which is important for divers to know for safe diving practices. Given that the mixture is composed of 10% oxygen, 50% helium, and the rest nitrogen, we can infer that nitrogen makes up 40% of the mix because the percentages must add up to 100%.
To find the partial pressure of nitrogen, we use the formula:
Partial pressure of nitrogen = Total pressure × Fraction of nitrogen
Substituting the given total pressure (2.07×104 kPa) and the fraction of nitrogen (40%, or 0.40), we get:
Partial pressure of nitrogen = 2.07×104 kPa × 0.40 = 8.28×103 kPa
However, since the options are listed in significant figures, we round the value to 8.3×103 kPa to match the option (d) in the given choices.