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Find the equation of the line in standard form that passes through the points (1,-1) and (2,-3)

User Ruben Daniels
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1 Answer

15 votes
15 votes

1. Find the slope

Slope = (y2 - y1)/(x2 - x1) = (-4 - (-3))/(-1 - 2) = 1/3

Slope = change in y / change in x

Translation: Every time y increases by 1/3, x increases by 1

OR, every time y increases by 1, x increases by 3

Both interpretations follow what we see when graphing the line.

2. Graph the line

3. Find the y-intercept

Definition of y-intercept: the value of y when x = 0

Start at the point (-1,-4), go up by 1/3 and right by 1, since that follows the slope we found and gets us to where x = 0

We know y = -4 when x = -1. If x moves right by 1 unit, then y must move up by 1/3 of a unit

(-4) + (1/3) = (-12/3) + (1/3) = -11/3 = y-intercept

4. Write this information in slope-intercept form:

Slope-Intercept Form: y = mx + b, where m is the slope and b is the y-intercept.

Plug in the values we found for the slope and y-intercept

y = (1/3)x + ((-11)/3) = (1/3)x - (11/3)

5. Convert to Standard Form

Standard Form: Ax + By = C where A, B, and C are constants

Manipulate the Slope-Intercept equation above to find the standard form

Multiply both sides of the slope-intercept form by 3

Subtract x from both sides of the equation

You get 3y - x = -11, which is the answer

User Slowjelj
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