Question

The electric field intensity between two plates separated by a distance of 0.75 cm is 1.42V/m. Determine the potential difference between the plates.

a) 0.00106 V
b) 0.0106 V
c) 0.106 V
d) 1.06 V

Answer 1

To find the potential difference between two plates with an electric field intensity of 1.42 V/m separated by 0.75 cm, use the formula V = E × d. Calculating this gives a potential difference of 0.0106 V, which is option b.

Step-by-step explanation:

To determine the potential difference between two plates when the electric field intensity and the distance between the plates are known, we can use the relationship:

Electric field (E) = Potential difference (V) / Distance (d)

Rearranging this formula to solve for the potential difference gives us:

V = E × d

Given that E = 1.42 V/m and d = 0.75 cm (which is 0.0075 m), we can substitute these values into the equation:

V = 1.42 V/m × 0.0075 m

V = 0.01065 V

This value rounds to 0.0106 V, which corresponds to option b. Therefore, the potential difference between the plates is 0.0106 V.