Question

The circuit she tests has a current of 3 j4 amps and a resistance of 4 – j6 ohms. what is the voltage of the circuit?

A) \(12 + j22\) V
B) \(18 - j10\) V
C) \(16 + j2\) V
D) \(8 - j12\) V

Answer 1

The voltage of the circuit is 12 + j22 V.

Step-by-step explanation:

To find the voltage of the circuit, we can use Ohm's Law, which states that voltage is equal to current multiplied by resistance. In this case, the current is 3 + j4 amps and the resistance is 4 - j6 ohms. So, the voltage would be:

Voltage = Current x Resistance

Voltage = (3 + j4) x (4 - j6)

Voltage = 12 + j22

Therefore, the voltage of the circuit is 12 + j22 volts.