Question

Let AA and BB be events in a sample space SS such that P(A)=0.34P(A)=0.34, P(B)=0.39P(B)=0.39, and P(A∩B)=0.19P(A∩B)=0.19. Find P(A∣B)P(A∣B).

a) 0.56
b) 0.49
c) 0.74
d) 0.61

Answer 1

The conditional probability of A given B is 0.4872.

Step-by-step explanation:

In this question, we are given that:

P(A) = 0.34, P(B) = 0.39, and P(A∩B) = 0.19.

To find P(A∣B), which represents the conditional probability of A given B, we use the formula:

P(A∣B) = P(A∩B) / P(B).

Substituting the given values, we get:

P(A∣B) = 0.19 / 0.39 = 0.4872.