Question

The altitude (in feet) of a rocket t s into flight is given by s = f(t) = −t3 51t2 540t 6 (t ≥ 0)?

a) 6 feet
b) 0 feet
c) -540 feet
d) 51 feet

Answer 1

The altitude of the rocket at the time of launch, given by the function at t = 0, is 6 feet.

Step-by-step explanation:

The student is asking about the altitude of a rocket at a particular time, given the altitude function s = f(t) = -t3 + 51t2 + 540t + 6 for t ≥ 0. To find the altitude of the rocket at the time of launch, we simply evaluate the function at t = 0. Substituting 0 into the function for t, we get s = f(0) = -03 + 51·02 + 540·0 + 6 = 6 feet, so the correct answer is (a) 6 feet.