Final answer:
The area of a square with a side length of 5 to the fourth units is found by squaring the side length. If '5 to the fourth' means 5 raised to the power of 4, then the area would be 625 units squared. When comparing two squares where the second square has side lengths twice as long, the larger square's area is 4 times greater than the smaller one because the area ratio corresponds to the scale factor squared.
Step-by-step explanation:
To find the area of a square with a side length of 5 to the fourth units, you would use the formula for the area of a square, which is side length squared (A = s²). In this case, if the side length of the square is 's', and s = 5 to the fourth units, then the area would be (5 to the fourth units)². However, it seems there might be a typo or misunderstanding in the phrase '5 to the fourth units.' If '5 to the fourth' means 5 raised to the power of 4, that would be 625, so the area would simply be 625 units squared (625 units²). If it literally means the side length is 'five' and units are to be taken to the fourth power, this part is not standard and requires clarification.
Consider an example where Marta has a square with a side length of 4 inches and a second square with dimensions that are twice the first. The side length of the second square would be 8 inches since you double the side length of the first square. To compare the areas of the two squares, you would square the scale factor. If the first square's area is 16 inches² (4 inches x 4 inches), the second square's area would be 64 inches² (8 inches x 8 inches), making it 4 times larger than the first square because the scale factor squared is 2² = 4.