Final answer:
The zeros (or solutions) to the quadratic equation f(x) = 3x² + 2x - 1 are -1/3 and 1.
Step-by-step explanation:
The zeros (or solutions) to the quadratic equation f(x) = 3x² + 2x - 1 can be found by setting the equation equal to zero and using the quadratic formula. The quadratic formula is given by:
x = (-b ± √(b² - 4ac)) / (2a)
For the given equation, the values of a, b, and c are:
Substituting these values into the quadratic formula gives us:
x = (-2 ± √(2² - 4(3)(-1))) / (2(3))
Simplifying this equation gives us the two solutions:
x = ( -2 ± √(4 + 12)) / 6
x = ( -2 ± √16) / 6
x = ( -2 ± 4) / 6
x = -1/3 or x = 1