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What are the zeros (solutions) to the following quadratic relations? f(x) = 3x² 2x - 1

User Crivateos
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Final answer:

The zeros (or solutions) to the quadratic equation f(x) = 3x² + 2x - 1 are -1/3 and 1.

Step-by-step explanation:

The zeros (or solutions) to the quadratic equation f(x) = 3x² + 2x - 1 can be found by setting the equation equal to zero and using the quadratic formula. The quadratic formula is given by:

x = (-b ± √(b² - 4ac)) / (2a)

For the given equation, the values of a, b, and c are:

  • a = 3
  • b = 2
  • c = -1

Substituting these values into the quadratic formula gives us:

x = (-2 ± √(2² - 4(3)(-1))) / (2(3))

Simplifying this equation gives us the two solutions:

x = ( -2 ± √(4 + 12)) / 6

x = ( -2 ± √16) / 6

x = ( -2 ± 4) / 6

x = -1/3 or x = 1

User Danny Kopping
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