Question

In a certain group of 53 students, 17 are taking accounting, 21 are taking chemistry, and 4 are taking both. What is the probability that a randomly chosen student is taking accounting or chemistry?

Answer 1

The probability that a randomly chosen student is taking accounting or chemistry can be found using the principle of inclusion-exclusion.

Step-by-step explanation:

To find the probability that a randomly chosen student is taking accounting or chemistry, we need to use the principle of inclusion-exclusion. The formula for this is:

P(A or B) = P(A) + P(B) - P(A and B)

In this case, P(A) is the probability of taking accounting, which is 17/53. P(B) is the probability of taking chemistry, which is 21/53. P(A and B) is the probability of taking both accounting and chemistry, which is 4/53. By substituting these values into the formula, we get:

P(Accounting or Chemistry) = 17/53 + 21/53 - 4/53 = 34/53

Therefore, the probability that a randomly chosen student is taking accounting or chemistry is 34/53.