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If 6.41 mol of an ideal gas has a pressure of 3.99 atm and a volume of 34.95 L, what is the temperature of the sample?

a) 353 K
b) 468 K
c) 524 K
d) 611 K

1 Answer

3 votes

Final answer:

In the student's question about finding the temperature of an ideal gas using the ideal gas law, we solved the equation T = PV/nR using the given values. The result of 264.1 K did not match any of the multiple-choice answers. The student should verify the given values and seek clarification if needed.

Step-by-step explanation:

The student's question involves calculating the temperature of a given sample of an ideal gas using the ideal gas law, which can be represented by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)), and T is temperature in kelvin. Given that the pressure is 3.99 atm, the volume is 34.95 L, and the amount of gas is 6.41 mol, we can rearrange the equation to solve for T.

T = \(\frac{PV}{nR}\) = \(\frac{(3.99 \text{ atm})(34.95 \text{ L})}{(6.41 \text{ mol})(0.0821 \text{ L\u00b7atm/(mol\u00b7K)})}\)

Carry out the calculation to find the temperature:

T = \(\frac{139.0055 \text{ L\u00b7atm}}{0.526161 \text{ L\u00b7atm/(mol\u00b7K)}}\) = 264.1 K

However, the calculation result does not match any of the multiple-choice options provided in the question. There might be an error in the question or in the calculation. If the calculations are correct, the student should ensure the values in the question were transcribed properly and seek clarification if necessary.

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