Question

If 9 lbs of a nut mix contains 12% peanuts is mixed with 20 lbs of nut mix that contains 36% peanuts, what is the concentration of peanuts in the final product? Round to the nearest whole percent.

a) 22%
b) 26%
c) 30%
d) 34%

Answer 1

The concentration of peanuts in the final mixture is calculated by dividing the total weight of peanuts by the combined weight of the mixes and multiplying by 100. The rounded result is 29%, which is not an option in the question, implying a possible error in the provided options.

Step-by-step explanation:

The question is asking for the final concentration of peanuts in a mixture of two different nut mixes. To find this, we will follow these steps:

1. Calculate the amount of peanuts in the first mix: 9 lbs × 12% = 1.08 lbs of peanuts.
2. Calculate the amount of peanuts in the second mix: 20 lbs × 36% = 7.2 lbs of peanuts.
3. Add the amount of peanuts from both mixes to get the total amount of peanuts: 1.08 lbs + 7.2 lbs = 8.28 lbs of peanuts.
4. Add the total weights of both mixes to get the total weight of the mixture: 9 lbs + 20 lbs = 29 lbs.
5. Divide the total weight of peanuts by the total weight of the mixture and multiply by 100 to get the percentage: (8.28 lbs / 29 lbs) × 100 = 28.55%, which we round to the nearest whole percent to get 29%.

Therefore, the concentration of peanuts in the final product is approximately 29%.