Question

The brakes are applied to a moving car, causing it to uniformly slow down. While slowing, it moves a distance of 40.0 m in 7.25 s to a final velocity of 1.20 m/s, at which point the brakes are released.

Answer 1

The car's acceleration while slowing down is 0.165 m/s².

Step-by-step explanation:

In this scenario, we are given that a car is slowing down uniformly and moves a distance of 40.0 m in 7.25 s to a final velocity of 1.20 m/s. We can use the equation:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Since the car is slowing down, the acceleration is negative. Rearranging the equation, we get:

a = (v - u) / t

Substituting the given values, we have:

a = (1.20 m/s - 0 m/s) / 7.25 s = 0.165 m/s²

Therefore, the car's acceleration while slowing down is 0.165 m/s².