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H₃PO₄(aq) + Sr(OH)₂(aq) → H₃PO₄(aq) + Sr(OH)₂(aq):

a. H₃PO₄(aq) + Sr(OH)₂(aq) → H₃PO₄(aq) + Sr(OH)₂(aq)

b. H₃PO₄(aq) + Sr(OH)₂(aq) → H₃PO₄(aq) + Sr₂(OH)₄(aq)

c. H₃PO₄(aq) + Sr(OH)₂(aq) → H₃PO₄(aq) + Sr₂(OH)₂(aq)

d. H₃PO₄(aq) + Sr(OH)₂(aq) → H₃PO₄(aq) + SrO(aq) + H₂O

User Rob Hunter
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1 Answer

3 votes

Final answer:

The correct balanced reaction between phosphoric acid (H₃PO₄(aq)) and strontium hydroxide (Sr(OH)₂(aq)) is not provided in the options given. It should result in strontium phosphate and water, represented by the balanced equation H₃PO₄(aq) + 3Sr(OH)₂(aq) → Sr₃(PO₄)₂(s) + 6H₂O(l).

Step-by-step explanation:

The chemical reaction between phosphoric acid (H₃PO₄(aq)) and strontium hydroxide (Sr(OH)₂(aq)) leads to the formation of a salt and water, which is a typical acid-base neutralization reaction. However, the reaction formula provided is incorrect as it merely repeats the reactants without showing the products or the balanced equation. From the options provided and referenced solutions, none reflects the correct reaction of phosphoric acid with strontium hydroxide. Instead, the correct balanced chemical equation should be:

H₃PO₄(aq) + 3Sr(OH)₂(aq) → Sr₃(PO₄)₂(s) + 6H₂O(l)

This equation demonstrates that three moles of strontium hydroxide react with one mole of phosphoric acid to produce one mole of strontium phosphate, a solid precipitate, and six moles of water.

User JerKimball
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