Question

Find the 22nd term of an arithmetic sequence where a^1 = 5 and the common difference is 4?

A) 93
B) 101
C) 109
D) 117.

Answer 1

To find the 22nd term of an arithmetic sequence with a first term of 5 and a common difference of 4, use the formula for the nth term of an arithmetic sequence and calculate it to be 89.

Step-by-step explanation:

The question asks to find the 22nd term of an arithmetic sequence where the first term a1 is 5 and the common difference is 4.

We use the formula for the nth term of an arithmetic sequence, which is:
an = a1 + (n - 1)d,

where an is the nth term, a1 is the first term, n is the term number and d is the common difference.

To find the 22nd term, we plug in the values:

a22 = 5 + (22 - 1)×4 = 5 + 21×4 = 5 + 84 = 89