Question

What is the first whole number value for x that proves y = 3 will surpass the function y = x^2 + 2?

A) x = 1
B) x = 2
C) x = 3
D) x = 4.

Answer 1

By substituting the given values into the equation
`y = x^2 + 2`, we see that for x = 2, y becomes 6, which is the first whole number value where y surpasses 3. Thus, the answer is B) x = 2.

Step-by-step explanation:

To find the first whole number value for x where y = 3 will surpass
`y = x^2 + 2`, we need to determine the point at which
`y = x^2 + 2` is just less than 3. We can do this by trying out each of the provided options:

• For x = 1:
  `y = 1^2 + 2 = 3`. At this point, y equals 3, not surpasses it.
• For x = 2:
  `y = 2^2 + 2 = 6`. Here, y is already greater than 3, but we are looking for the first time it gets surpassed.
• For x = 3: Upon checking, we get
  `y = 3^2 + 2 = 11`, which is much larger than 3.
• There is no need to check x = 4 as we have already found that x = 2 surpasses y = 3.

Therefore, the answer is B) x = 2. This is the first whole number value for x at which y = 3 is surpassed.