Question

You have 1.5 L of a 1.5 M solution of acetic acid. How many moles of CH3COOH is that?

A) 1 mole
B) 2.25 moles
C) 3.375 moles
D) 1.5 moles.

Answer 1

To find the number of moles of acetic acid in a 1.5 L solution with 1.5 M concentration, multiply the volume by the molarity, resulting in 2.25 moles of acetic acid.

The correct answer is B.

Step-by-step explanation:

To calculate the number of moles of acetic acid in a solution from its volume and molarity, you would multiply the volume of the solution by its molarity. Given a 1.5 L solution of acetic acid with a molarity of 1.5 M, the calculation is:

Number of moles = Volume (L) × Molarity (M)

Number of moles = 1.5 L × 1.5 M

Number of moles = 2.25 moles of CH₃COOH

The correct answer is B) 2.25 moles.