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A car entered I696 at an initial velocity of 45 m/s, after accelerating, the car’s final velocity was 125 m/s. What was the car’s average velocity?

(A) 65 m/s
(B) 85 m/s
(C) 105 m/s
(D) 125 m/s

1 Answer

6 votes

Final answer:

The average velocity of a car that accelerates from 45 m/s to 125 m/s is 85 m/s, which is calculated by taking the sum of the initial and final velocities and dividing by two.

Step-by-step explanation:

The question involves calculating the average velocity of a car that accelerates from an initial velocity to a final velocity. To find the average velocity when acceleration is constant, you take the sum of the initial and final velocities and divide by two. Therefore, for a car that starts with an initial velocity of 45 m/s and reaches a final velocity of 125 m/s, the average velocity (Vavg) is calculated as:

Vavg = (Vi + Vf) / 2

Vavg = (45 m/s + 125 m/s) / 2

Vavg = 170 m/s / 2

Vavg = 85 m/

So, the correct answer is (B) 85 m/s.

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