Final answer:
To accumulate $10,000 in ten years with an interest rate of 10% compounded annually, one would need to deposit $3,853.49 today.
Step-by-step explanation:
The question revolves around the concept of compound interest, which is a common topic in high school mathematics. Specifically, it asks how much money needs to be deposited today in an account with a 10% annual interest rate to have $10,000 after ten years. To calculate this, we use the formula for compound interest:
P = A / (1 + r)^n
Where:
P is the principal amount (the initial amount deposited)
- A is the amount of money accumulated after n years, including interest.
- r is the annual interest rate (decimal)
- n is the number of years the money is invested or borrowed for
In this case, A is $10,000, r is 0.10 (10%), and n is 10 years.
Plugging the numbers into the equation, we get:
P = $10,000 / (1 + 0.10)^10
P = $10,000 / (1.10)^10
P = $10,000 / 2.59374
P = $3,853.49 (rounded to two decimal places)
Therefore, you would need to deposit $3,853.49 today to have $10,000 in ten years with an annual compounding interest rate of 10%.