Final answer:
To find the number of potassium ions in 30.0 mL of 0.600 M K2CO3 solution, calculate the moles of K2CO3 and then use Avogadro's number to find that there are approximately 2.17 x 10^22 potassium ions.
Step-by-step explanation:
The question is asking how many potassium ions are present in 30.0 mL of 0.600 M K₂CO₃ solution. To find the number of potassium ions, we first need to determine how many moles of K₂CO₃ are present in 30.0 mL (or 0.030 L) of solution. Using the molarity equation M = moles/L, we find:
moles of K₂CO₃ = Molarity (M) × Volume (L) = 0.600 M × 0.030 L = 0.018 moles K₂CO₃
Each molecule of K₂CO₃ contains two potassium ions, so:
Total number of K+ ions = 2 × moles of K₂CO₃
Total number of K+ ions = 2 × 0.018 moles = 0.036 moles of K+ ions
To convert moles of K+ ions to the number of ions, we use Avogadro's number (6.022 × 1023 ions/mole):
Number of K+ ions = 0.036 moles × (6.022 × 1023 ions/mole)
Number of K+ ions ≈ 2.17 × 1022 ions.
Therefore, there are approximately 2.17 × 1022 potassium ions in 30.0 mL of 0.600 M K₂CO₃ solution.