Question

How many milliliters of a 5.0gml potassium hydroxide solution is required to create 200ml of solution with a concentration of 2.0gml?

Answer 1

To prepare 200 mL of a 2.0 g/mL potassium hydroxide solution from a 5.0 g/mL stock solution, you would require 80 mL of the stock solution.

Step-by-step explanation:

To calculate the volume of a 5.0 g/mL potassium hydroxide solution needed to create 200 mL of a 2.0 g/mL solution, you can use the dilution formula: C1V1 = C2V2, where C1 is the concentration of the initial solution, V1 is the volume of the initial solution needed, C2 is the concentration of the final solution, and V2 is the volume of the final solution.

Let's fill in what we know:

• C1 = 5.0 g/mL (concentration of the potassium hydroxide stock solution)
• V1 = ? (This is what we're solving for)
• C2 = 2.0 g/mL (desired concentration of the diluted solution)
• V2 = 200 mL (final volume of the diluted solution)

Now, plug these values into the formula:

(5.0 g/mL) × V1 = (2.0 g/mL) × (200 mL)

Show work:

(5.0 g/mL) × V1 = 400 g

V1 = 400 g / (5.0 g/mL)

V1 = 80 mL

Therefore, you would need 80 mL of the 5.0 g/mL potassium hydroxide solution to create 200 mL of a 2.0 g/mL solution.