49.0k views
3 votes
How many milliliters of a 2.5 m MgCl, solution contain 17.5 g MgCl?

User DexBG
by
6.6k points

1 Answer

0 votes

Final answer:

To calculate the volume of a 2.5 M MgCl2 solution needed to contain 17.5 g of MgCl2, you can use the formula moles = mass / molar mass. After calculating the moles, use the formula volume = moles / Molarity to find the volume in liters. Finally, convert the volume to milliliters by multiplying by 1000.

Step-by-step explanation:

To determine the number of milliliters of a 2.5 M MgCl2 solution that contain 17.5 g of MgCl2, we can use the equation:

moles = mass / molar mass

First, calculate the moles of MgCl2 with the given mass:

moles = 17.5 g / 95.21 g/mol

Next, use the definition of molarity to calculate the volume (in liters) of the solution:

Molarity = moles / volume (in liters)

Since the given solution is 2.5 M, we can rearrange the equation to solve for volume:

Volume (in liters) = moles / Molarity

The volume will be in liters, so to convert it to milliliters, multiply by 1000:

Volume (in milliliters) = (moles / Molarity) * 1000

Substituting the values, we get:

Volume (in milliliters) = (17.5 g / 95.21 g/mol) / 2.5 mol/L * 1000

After performing the calculation, the answer is the number of milliliters of the 2.5 M MgCl2 solution that contain 17.5 g of MgCl2.