Question

How many moles of hydrogen are needed to form 3.82 moles of water, according to the following equation: 2H₂ + O₂ → 2H₂O

Answer 1

Using the stoichiometric ratio from the balanced chemical equation 2H₂ + O₂ → 2H₂O, it is determined that 3.82 moles of hydrogen are needed to produce 3.82 moles of water.

Step-by-step explanation:

To determine how many moles of hydrogen are required to form 3.82 moles of water, we refer to the balanced chemical equation 2H₂ + O₂ → 2H₂O. According to the equation, two moles of hydrogen react with one mole of oxygen to produce two moles of water. Using this stoichiometric ratio, we can set up a conversion factor that shows the relationship between hydrogen and water in terms of moles:

1. Determine the mole ratio from the equation: 2 mol H₂ / 2 mol H₂O.
2. Use the mole ratio to find the amount of hydrogen needed for 3.82 moles of water: (3.82 mol H₂O) × (2 mol H₂ / 2 mol H₂O).
3. Simplify the equation and calculate: 3.82 mol H₂O × 1 = 3.82 mol H₂.

Therefore, 3.82 moles of hydrogen are needed to produce 3.82 moles of water.

Answer 2

To form 3.82 moles of water, 3.82 moles of hydrogen are needed according to the balanced chemical equation 2 H₂ + O₂ → 2 H₂O.

Step-by-step explanation:

To find out how many moles of hydrogen are needed to form 3.82 moles of water, we must consider the balanced chemical equation:

2 H₂ + O₂ → 2 H₂O

This equation shows that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water. Thus, the ratio of hydrogen to water is 1:1 according to the coefficients in the balanced equation. To form 3.82 moles of water, you would need the same number of moles of hydrogen, which is 3.82 moles, as they are directly related in a 1:1 ratio in the reaction.