Question

How many molecules of C₄H₁₀ are present in 5.6 grams of C₄H₁₀ ? Hint: 2 conversion factors are needed. Avogadro's number and molecular weight. atomic weights to use: c = 12 h = 1.

Answer 1

To determine the number of molecules in 5.6 grams of butane (C4H10), we first convert the mass to moles using its molar mass, and then multiply by Avogadro's number, resulting in approximately 5.8 x 10²² molecules.

Step-by-step explanation:

The subject of this question is determining how many molecules of butane (C₄H₁₀) are present in 5.6 grams. To find this, we need to use the molecular weight and Avogadro's number. The molecular weight of butane can be calculated by adding the weights of carbon (C, 12 amu each) and hydrogen (H, 1 amu each), resulting in a molecular weight of 58 amu (4 C atoms * 12 + 10 H atoms * 1 = 58 g/mol).

First, we convert the mass of butane to moles using the molar mass:

5.6 grams C₄H₁₀ × 1 mole C₄H₁₀ / 58 g C₄H₁₀ = 0.0966 moles of C₄H₁₀

Next, to find the number of molecules, we multiply the number of moles by Avogadro's number:

0.0966 moles C₄H₁₀ × 6.022 × 1023 molecules / 1 mole C₄H₁₀ = 5.8 × 1022 molecules of C₄H₁₀