Final answer:
There are 4.044 moles of nitrogen in 89.0 g of nitrous oxide. This is calculated using the molar mass of nitrous oxide (44.02 g/mol) and the fact that each molecule of N₂O contains two atoms of nitrogen.
Step-by-step explanation:
To calculate the number of moles of nitrogen in 89.0 g of nitrous oxide (N₂O), you need to use the molar mass of N₂O, which is 44.02 g/mol. The molar mass is derived from the atomic masses of nitrogen (N, 14.01 g/mol for each atom) and oxygen (O, 16.00 g/mol).
First, determine how many moles of N₂O are in 89.0 g:
89.0 g N₂O × (1 mol N₂O / 44.02 g) = 2.022 moles of N₂O
Since each molecule of N₂O contains two atoms of nitrogen, to find the moles of nitrogen atoms, you would multiply the moles of N₂O by two:
2.022 moles N₂O × 2 = 4.044 moles of nitrogen
So, there are 4.044 moles of nitrogen in 89.0 g of nitrous oxide.