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How many moles of nutrasweet, C14H18N2O5, are present in 23.6 grams of nutrasweet?

User Axelbrz
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1 Answer

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Final answer:

23.6 grams of Nutrasweet (C14H18N2O5) equals 0.0802 moles, calculated by dividing the mass by the molar mass of Nutrasweet (294.3 g/mol).

Step-by-step explanation:

To calculate the number of moles of Nutrasweet (C14H18N2O5) present in 23.6 grams of Nutrasweet, we first need to determine its molar mass. The molar mass is calculated by summing the atomic masses of all the atoms in the molecule:

  • Carbon (C): 14 atoms × 12.01 g/mol = 168.14 g/mol
  • Hydrogen (H): 18 atoms × 1.008 g/mol = 18.14 g/mol
  • Nitrogen (N): 2 atoms × 14.01 g/mol = 28.02 g/mol
  • Oxygen (O): 5 atoms × 16.00 g/mol = 80.00 g/mol

Adding these together gives us a molar mass for Nutrasweet of 294.3 g/mol. Next, we use the formula:

number of moles = mass (g) ÷ molar mass (g/mol)

So, the number of moles of Nutrasweet in 23.6 grams is:

23.6 g ÷ 294.3 g/mol = 0.0802 moles

This result is consistent with our rough estimate for such calculations.

User Sieabah
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