Question

In a reaction, 23.55 ml of 1.37 M NaOH were added to an acid. How many moles of NaOH were added?

A) 0.0322 moles
B) 0.0327 moles
C) 0.0508 moles
D) 0.0513 moles

Answer 1

To find the number of moles of NaOH added to the acid, we multiply the molarity by the volume in liters, yielding approximately 0.0322 moles.

Step-by-step explanation:

To calculate the number of moles of NaOH added in the reaction, we use the formula:

Molarity (M) = number of moles of solute (mol) / Volume of solution in liters (L)

First, we convert the volume from milliliters to liters:

• 23.55 mL = 0.02355 L

Then, using the molarity of the NaOH solution, we calculate the moles of NaOH:

• 1.37 M = x mol / 0.02355 L
• x = 1.37 M * 0.02355 L
• x = 0.032265 mol

The closest answer to 0.032265 mol is 0.0322 moles (Option A).