The solution to the inequality 3600 + 1.02x < 2000 + 1.04x is x > 80000.
To solve algebraically for x in the inequality 3600 + 1.02x < 2000 + 1.04x, we need to isolate x on one side of the inequality. Here are the steps:
Subtract 3600 from both sides of the inequality:
3600 + 1.02x - 3600 < 2000 + 1.04x - 3600
1.02x < -1600 + 1.04x
Subtract 1.04x from both sides of the inequality:
1.02x - 1.04x < -1600
-0.02x < -1600
Divide both sides of the inequality by -0.02 (remember to flip the inequality sign since we are dividing by a negative number):
x > 80000
Therefore, the solution to the inequality 3600 + 1.02x < 2000 + 1.04x is x > 80000.
Complete question:
Solve algebraically for X. 3600 + 1.02x < 2000 + 1.04x